Copyright: R. Paul Singh
|
Item |
Correction |
| Example
1.1 (p8) |
In part d, the pressure used in calculation should be 29.38 psia (and not 29.28), the calculated pressure should be 202567 Pa or 202.57 kPa.
In alternative calculation, converting 29.38 psia will give 202.58 kPa |
| Example
2.10 (p105) |
Step (1) should read P1=P3=Patm |
| Equation 2.145 (p146) |
On the left hand side, replace uB with u2. |
| Problem
2.8 (p179) |
pressure
drop is 78.86kPa |
| Problem
2.10 (p180) |
Cf
should be 3 |
| Problem 2.13 (p180) |
mass flow rate = 23 kg/s |
| Example
3.6 (p242) |
Assume
cp of pudding = 4 kJ/kgC |
| Equation 4.85 (p303) |
In this equation the = and + signs are missing, see equation (4.84) for correct placement of these signs. |
| Example
4.29 (p 376) |
The
relative dielectric constant is 64 |
| Problem
4.52 (p391) |
Final
temperature = 128 C |
| Page
518 (line# 7) |
Latent
heat = 333.3 kJ/kg |
| Example
7.1(p 519) |
Convective
heat transfer coefficient = 50 W/m^2 C |
| Example
12.7 (p677) |
In step
3, change 2354 to 2365.5, in step 5, change 2.82 to 2.834 in step
7, change 1.276 to 1.282,and in step 9, change 3.077 to 3.08 |
| Table A.2.9 (p786) |
Eqn for k (thermal conductivity) for Fat: change 2.7604 x 10^-3T to 2.7604 x 10^-4T |
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